3w-5+4(2w+3)=-3(w+1)

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Solution for 3w-5+4(2w+3)=-3(w+1) equation: 



3w-5+4(2w+3)=-3(w+1)

We move all terms to the left:

3w-5+4(2w+3)-(-3(w+1))=0

We multiply parentheses

3w+8w-(-3(w+1))+12-5=0



We calculate terms in parentheses: -(-3(w+1)), so:

-3(w+1)

We multiply parentheses

-3w-3

Back to the equation:

-(-3w-3)



We add all the numbers together, and all the variables

11w-(-3w-3)+7=0

We get rid of parentheses

11w+3w+3+7=0

We add all the numbers together, and all the variables

14w+10=0

We move all terms containing w to the left, all other terms to the right

14w=-10

w=-10/14

w=-5/7

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