If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3w^2+6w+3=0
a = 3; b = 6; c = +3;
Δ = b2-4ac
Δ = 62-4·3·3
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$w=\frac{-b}{2a}=\frac{-6}{6}=-1$
| (7)(9)=p21 | | x+(x+1)*(x+2)=30 | | 2x(3)=54 | | 8x+360=-4 | | 10^(x-2)-19=821 | | x3+4x2+6x+4=0 | | 8y-9+3(2y+3)=-2(y+9) | | 70=-8x+36 | | 1x-42+48=10 | | –6+8u=4+9u | | –6+8u=4+9uu | | 5(u-2)-8=-4(-5u+7)-7u | | 3f=17.34 | | 7x+25-5=48 | | 6.5x+12=-24+11 | | b100=35. | | 4(3n+2)=6(8n+3)+7 | | 2y-1=-28 | | 75x+350=100x+20 | | -11x-73=18-3 | | ¾(8x+4)=6 | | −3x+4=−8x−26 | | b100=35 | | b100=3.5 | | 96°+2x+(x+12°)=180° | | 5(x+5)−5=48−2x | | 3.5*x=12 | | N=4x78 | | -3+b/3=0 | | -52=4(2x-3) | | 9x+12=3x-18 | | 14v+81=0 |