If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3w^2-24w=0
a = 3; b = -24; c = 0;
Δ = b2-4ac
Δ = -242-4·3·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24}{2*3}=\frac{0}{6} =0 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24}{2*3}=\frac{48}{6} =8 $
| 2n+150=1500 | | 38a+1=39a+2 | | 6(y+8)+3y=39 | | 6b+3=3=13 | | x*0.10=100365.12 | | 7c+9=11c-35 | | 5x-6=12-6 | | -2x+4x-17=2(x-1)-22 | | 12n=4n+4 | | 4x-(1+x)=8 | | 3y-5=23 | | 4x-1+x=8 | | 8*z=24 | | 19x+-17=-11x+3 | | 5x(3+2x)=0 | | 6n+4=3n+8 | | (34+x)+(2×25)=104 | | 34+x+10=104 | | -5x+9-6(x-1)=-(4x-7)-6x+6 | | 1/2(z+3.5)=4.5 | | 4g+1=-3 | | 2z/7+7=10 | | 4x^2–16=0 | | 4x2–16=0 | | (3+x)÷2=3.5 | | x*1.3=183095 | | 3x+11-7x=4 | | 3x+11-7x=3 | | 3x+11-7x=2 | | u÷11=7 | | 9x-7=2x-91 | | 1.3=-9.3w-6.1w |