3x(-12)-16-5x=40

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Solution for 3x(-12)-16-5x=40 equation:



3x(-12)-16-5x=40
We move all terms to the left:
3x(-12)-16-5x-(40)=0
We add all the numbers together, and all the variables
-5x+3x(-12)-56=0
We multiply parentheses
-5x-36x-56=0
We add all the numbers together, and all the variables
-41x-56=0
We move all terms containing x to the left, all other terms to the right
-41x=56
x=56/-41
x=-1+15/41

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