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3x(-2x-7)=15

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Solution for 3x(-2x-7)=15 equation:



3x(-2x-7)=15
We move all terms to the left:
3x(-2x-7)-(15)=0
We multiply parentheses
-6x^2-21x-15=0
a = -6; b = -21; c = -15;
Δ = b2-4ac
Δ = -212-4·(-6)·(-15)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
x_{1}=\frac{-b-\sqrt{\Delta}}{2a}
x_{2}=\frac{-b+\sqrt{\Delta}}{2a}

\sqrt{\Delta}=\sqrt{81}=9
x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-9}{2*-6}=\frac{12}{-12} =-1
x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+9}{2*-6}=\frac{30}{-12} =-2+1/2

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