3x(-3+x)=-5

Solution for 3x(-3+x)=-5 equation:

3x(-3+x)=-5

We move all terms to the left:

3x(-3+x)-(-5)=0

We add all the numbers together, and all the variables

3x(x-3)-(-5)=0

We add all the numbers together, and all the variables

3x(x-3)+5=0

We multiply parentheses

3x^2-9x+5=0

a = 3; b = -9; c = +5;
Δ = b2-4ac
Δ = -92-4·3·5
Δ = 21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{21}}{2*3}=\frac{9-\sqrt{21}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{21}}{2*3}=\frac{9+\sqrt{21}}{6}
$