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3x(-4-5x)=0
We add all the numbers together, and all the variables
3x(-5x-4)=0
We multiply parentheses
-15x^2-12x=0
a = -15; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·(-15)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*-15}=\frac{0}{-30} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*-15}=\frac{24}{-30} =-4/5 $
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