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3x(-7+x)-11=29
We move all terms to the left:
3x(-7+x)-11-(29)=0
We add all the numbers together, and all the variables
3x(x-7)-11-29=0
We add all the numbers together, and all the variables
3x(x-7)-40=0
We multiply parentheses
3x^2-21x-40=0
a = 3; b = -21; c = -40;
Δ = b2-4ac
Δ = -212-4·3·(-40)
Δ = 921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-\sqrt{921}}{2*3}=\frac{21-\sqrt{921}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+\sqrt{921}}{2*3}=\frac{21+\sqrt{921}}{6} $
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