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3x(-x+5)=2
We move all terms to the left:
3x(-x+5)-(2)=0
We add all the numbers together, and all the variables
3x(-1x+5)-2=0
We multiply parentheses
-3x^2+15x-2=0
a = -3; b = 15; c = -2;
Δ = b2-4ac
Δ = 152-4·(-3)·(-2)
Δ = 201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{201}}{2*-3}=\frac{-15-\sqrt{201}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{201}}{2*-3}=\frac{-15+\sqrt{201}}{-6} $
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