3x(0.67-0.156)=64x2/5

Solution for 3x(0.67-0.156)=64x2/5 equation:

3x(0.67-0.156)=64x^2/5

We move all terms to the left:

3x(0.67-0.156)-(64x^2/5)=0

We add all the numbers together, and all the variables

3x(0.514)-(64x^2/5)=0

We multiply parentheses

1.542x-(64x^2/5)=0

We get rid of parentheses

-64x^2/5+1.542x=0

We multiply all the terms by the denominator


-64x^2+(1.542x)*5=0

We add all the numbers together, and all the variables

-64x^2+(+1.542x)*5=0

We multiply parentheses

-64x^2+5x=0

a = -64; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-64)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-64}=\frac{-10}{-128}
=5/64
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-64}=\frac{0}{-128}
=0
$