3x(1+x)=36

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Solution for 3x(1+x)=36 equation:


Simplifying
3x(1 + x) = 36
(1 * 3x + x * 3x) = 36
(3x + 3x2) = 36

Solving
3x + 3x2 = 36

Solving for variable 'x'.

Reorder the terms:
-36 + 3x + 3x2 = 36 + -36

Combine like terms: 36 + -36 = 0
-36 + 3x + 3x2 = 0

Factor out the Greatest Common Factor (GCF), '3'.
3(-12 + x + x2) = 0

Factor a trinomial.
3((-4 + -1x)(3 + -1x)) = 0

Ignore the factor 3.

Subproblem 1

Set the factor '(-4 + -1x)' equal to zero and attempt to solve: Simplifying -4 + -1x = 0 Solving -4 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -1x = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -1x = 0 + 4 -1x = 0 + 4 Combine like terms: 0 + 4 = 4 -1x = 4 Divide each side by '-1'. x = -4 Simplifying x = -4

Subproblem 2

Set the factor '(3 + -1x)' equal to zero and attempt to solve: Simplifying 3 + -1x = 0 Solving 3 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -1x = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -1x = 0 + -3 -1x = 0 + -3 Combine like terms: 0 + -3 = -3 -1x = -3 Divide each side by '-1'. x = 3 Simplifying x = 3

Solution

x = {-4, 3}

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