3x(1-x)+4(x-1)=0

Solution for 3x(1-x)+4(x-1)=0 equation:

3x(1-x)+4(x-1)=0

We add all the numbers together, and all the variables

3x(-1x+1)+4(x-1)=0

We multiply parentheses

-3x^2+3x+4x-4=0

We add all the numbers together, and all the variables

-3x^2+7x-4=0

a = -3; b = 7; c = -4;
Δ = b2-4ac
Δ = 72-4·(-3)·(-4)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-1}{2*-3}=\frac{-8}{-6}
=1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+1}{2*-3}=\frac{-6}{-6}
=1
$