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3x(1-x)=9-5x
We move all terms to the left:
3x(1-x)-(9-5x)=0
We add all the numbers together, and all the variables
3x(-1x+1)-(-5x+9)=0
We multiply parentheses
-3x^2+3x-(-5x+9)=0
We get rid of parentheses
-3x^2+3x+5x-9=0
We add all the numbers together, and all the variables
-3x^2+8x-9=0
a = -3; b = 8; c = -9;
Δ = b2-4ac
Δ = 82-4·(-3)·(-9)
Δ = -44
Delta is less than zero, so there is no solution for the equation
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