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3x(10x-15)=180
We move all terms to the left:
3x(10x-15)-(180)=0
We multiply parentheses
30x^2-45x-180=0
a = 30; b = -45; c = -180;
Δ = b2-4ac
Δ = -452-4·30·(-180)
Δ = 23625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{23625}=\sqrt{225*105}=\sqrt{225}*\sqrt{105}=15\sqrt{105}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-15\sqrt{105}}{2*30}=\frac{45-15\sqrt{105}}{60} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+15\sqrt{105}}{2*30}=\frac{45+15\sqrt{105}}{60} $
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