3x(1625/3x)=1625

Solution for 3x(1625/3x)=1625 equation:

3x(1625/3x)=1625

We move all terms to the left:

3x(1625/3x)-(1625)=0


Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

3x(+1625/3x)-1625=0

We multiply parentheses

4875x^2-1625=0

a = 4875; b = 0; c = -1625;
Δ = b2-4ac
Δ = 02-4·4875·(-1625)
Δ = 31687500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{31687500}=\sqrt{10562500*3}=\sqrt{10562500}*\sqrt{3}=3250\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-3250\sqrt{3}}{2*4875}=\frac{0-3250\sqrt{3}}{9750}
=-\frac{3250\sqrt{3}}{9750}
=-\frac{\sqrt{3}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+3250\sqrt{3}}{2*4875}=\frac{0+3250\sqrt{3}}{9750}
=\frac{3250\sqrt{3}}{9750}
=\frac{\sqrt{3}}{3}
$