3x(2)+4x=180

Solution for 3x(2)+4x=180 equation:

3x(2)+4x=180

We move all terms to the left:

3x(2)+4x-(180)=0

We add all the numbers together, and all the variables

3x^2+4x-180=0

a = 3; b = 4; c = -180;
Δ = b2-4ac
Δ = 42-4·3·(-180)
Δ = 2176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2176}=\sqrt{64*34}=\sqrt{64}*\sqrt{34}=8\sqrt{34}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-8\sqrt{34}}{2*3}=\frac{-4-8\sqrt{34}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+8\sqrt{34}}{2*3}=\frac{-4+8\sqrt{34}}{6}
$