3x(2)+6x-6=-2X(2)

Solution for 3x(2)+6x-6=-2X(2) equation:

3x(2)+6x-6=-2x(2)

We move all terms to the left:

3x(2)+6x-6-(-2x(2))=0

We add all the numbers together, and all the variables

-(-2x^2)+3x2+6x-6=0

We add all the numbers together, and all the variables

3x^2-(-2x^2)+6x-6=0

We get rid of parentheses

3x^2+2x^2+6x-6=0

We add all the numbers together, and all the variables

5x^2+6x-6=0

a = 5; b = 6; c = -6;
Δ = b2-4ac
Δ = 62-4·5·(-6)
Δ = 156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{156}=\sqrt{4*39}=\sqrt{4}*\sqrt{39}=2\sqrt{39}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{39}}{2*5}=\frac{-6-2\sqrt{39}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{39}}{2*5}=\frac{-6+2\sqrt{39}}{10}
$