3x(2+2x)=2x-(3+2x)

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Solution for 3x(2+2x)=2x-(3+2x) equation:



3x(2+2x)=2x-(3+2x)
We move all terms to the left:
3x(2+2x)-(2x-(3+2x))=0
We add all the numbers together, and all the variables
3x(2x+2)-(2x-(2x+3))=0
We multiply parentheses
6x^2+6x-(2x-(2x+3))=0
We calculate terms in parentheses: -(2x-(2x+3)), so:
2x-(2x+3)
We get rid of parentheses
2x-2x-3
We add all the numbers together, and all the variables
-3
Back to the equation:
-(-3)
We add all the numbers together, and all the variables
6x^2+6x+3=0
a = 6; b = 6; c = +3;
Δ = b2-4ac
Δ = 62-4·6·3
Δ = -36
Delta is less than zero, so there is no solution for the equation

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