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3x(2+4x)=5x-1
We move all terms to the left:
3x(2+4x)-(5x-1)=0
We add all the numbers together, and all the variables
3x(4x+2)-(5x-1)=0
We multiply parentheses
12x^2+6x-(5x-1)=0
We get rid of parentheses
12x^2+6x-5x+1=0
We add all the numbers together, and all the variables
12x^2+x+1=0
a = 12; b = 1; c = +1;
Δ = b2-4ac
Δ = 12-4·12·1
Δ = -47
Delta is less than zero, so there is no solution for the equation
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