3x(2+x)=x(2x-2)-24

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Solution for 3x(2+x)=x(2x-2)-24 equation: 



3x(2+x)=x(2x-2)-24

We move all terms to the left:

3x(2+x)-(x(2x-2)-24)=0

We add all the numbers together, and all the variables

3x(x+2)-(x(2x-2)-24)=0

We multiply parentheses

3x^2+6x-(x(2x-2)-24)=0



We calculate terms in parentheses: -(x(2x-2)-24), so:

x(2x-2)-24

We multiply parentheses

2x^2-2x-24

Back to the equation:

-(2x^2-2x-24)



We get rid of parentheses

3x^2-2x^2+6x+2x+24=0

We add all the numbers together, and all the variables

x^2+8x+24=0

a = 1; b = 8; c = +24;
Δ = b2-4ac
Δ = 82-4·1·24
Δ = -32
Delta is less than zero, so there is no solution for the equation

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