3x(2+x)=x(3x-2)

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Solution for 3x(2+x)=x(3x-2) equation:



3x(2+x)=x(3x-2)
We move all terms to the left:
3x(2+x)-(x(3x-2))=0
We add all the numbers together, and all the variables
3x(x+2)-(x(3x-2))=0
We multiply parentheses
3x^2+6x-(x(3x-2))=0
We calculate terms in parentheses: -(x(3x-2)), so:
x(3x-2)
We multiply parentheses
3x^2-2x
Back to the equation:
-(3x^2-2x)
We get rid of parentheses
3x^2-3x^2+6x+2x=0
We add all the numbers together, and all the variables
8x=0
x=0/8
x=0

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