3x(2+x)=x(3x-2)

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Solution for 3x(2+x)=x(3x-2) equation: 



3x(2+x)=x(3x-2)

We move all terms to the left:

3x(2+x)-(x(3x-2))=0

We add all the numbers together, and all the variables

3x(x+2)-(x(3x-2))=0

We multiply parentheses

3x^2+6x-(x(3x-2))=0



We calculate terms in parentheses: -(x(3x-2)), so:

x(3x-2)

We multiply parentheses

3x^2-2x

Back to the equation:

-(3x^2-2x)



We get rid of parentheses

3x^2-3x^2+6x+2x=0

We add all the numbers together, and all the variables

8x=0

x=0/8

x=0

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