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3x(2-4x)=4x(3x+2)+10
We move all terms to the left:
3x(2-4x)-(4x(3x+2)+10)=0
We add all the numbers together, and all the variables
3x(-4x+2)-(4x(3x+2)+10)=0
We multiply parentheses
-12x^2+6x-(4x(3x+2)+10)=0
We calculate terms in parentheses: -(4x(3x+2)+10), so:We get rid of parentheses
4x(3x+2)+10
We multiply parentheses
12x^2+8x+10
Back to the equation:
-(12x^2+8x+10)
-12x^2-12x^2+6x-8x-10=0
We add all the numbers together, and all the variables
-24x^2-2x-10=0
a = -24; b = -2; c = -10;
Δ = b2-4ac
Δ = -22-4·(-24)·(-10)
Δ = -956
Delta is less than zero, so there is no solution for the equation
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