3x(2-x)+4=5-(3x-10)

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Solution for 3x(2-x)+4=5-(3x-10) equation: 



3x(2-x)+4=5-(3x-10)

We move all terms to the left:

3x(2-x)+4-(5-(3x-10))=0

We add all the numbers together, and all the variables

3x(-1x+2)-(5-(3x-10))+4=0

We multiply parentheses

-3x^2+6x-(5-(3x-10))+4=0



We calculate terms in parentheses: -(5-(3x-10)), so:

5-(3x-10)

determiningTheFunctionDomain
-(3x-10)+5

We get rid of parentheses

-3x+10+5

We add all the numbers together, and all the variables

-3x+15

Back to the equation:

-(-3x+15)



We get rid of parentheses

-3x^2+6x+3x-15+4=0

We add all the numbers together, and all the variables

-3x^2+9x-11=0

a = -3; b = 9; c = -11;
Δ = b2-4ac
Δ = 92-4·(-3)·(-11)
Δ = -51
Delta is less than zero, so there is no solution for the equation

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