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3x(2/3)=375
We move all terms to the left:
3x(2/3)-(375)=0
We add all the numbers together, and all the variables
3x(+2/3)-375=0
We multiply parentheses
6x^2-375=0
a = 6; b = 0; c = -375;
Δ = b2-4ac
Δ = 02-4·6·(-375)
Δ = 9000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9000}=\sqrt{900*10}=\sqrt{900}*\sqrt{10}=30\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-30\sqrt{10}}{2*6}=\frac{0-30\sqrt{10}}{12} =-\frac{30\sqrt{10}}{12} =-\frac{5\sqrt{10}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+30\sqrt{10}}{2*6}=\frac{0+30\sqrt{10}}{12} =\frac{30\sqrt{10}}{12} =\frac{5\sqrt{10}}{2} $
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