3x(24x+29)=0

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Solution for 3x(24x+29)=0 equation:



3x(24x+29)=0
We multiply parentheses
72x^2+87x=0
a = 72; b = 87; c = 0;
Δ = b2-4ac
Δ = 872-4·72·0
Δ = 7569
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7569}=87$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(87)-87}{2*72}=\frac{-174}{144} =-1+5/24 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(87)+87}{2*72}=\frac{0}{144} =0 $

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