3x(2x)=6(20-x)

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Solution for 3x(2x)=6(20-x) equation: 



3x(2x)=6(20-x)

We move all terms to the left:

3x(2x)-(6(20-x))=0

We add all the numbers together, and all the variables

3x2x-(6(-1x+20))=0



We calculate terms in parentheses: -(6(-1x+20)), so:

6(-1x+20)

We multiply parentheses

-6x+120

Back to the equation:

-(-6x+120)



We get rid of parentheses

3x2x+6x-120=0

We add all the numbers together, and all the variables

6x+3x2x-120=0

We move all terms containing x to the left, all other terms to the right

6x+3x2x=120

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