3x(2x+1)=3(x+1)-3(4-2x)

Solution for 3x(2x+1)=3(x+1)-3(4-2x) equation:

3x(2x+1)=3(x+1)-3(4-2x)

We move all terms to the left:

3x(2x+1)-(3(x+1)-3(4-2x))=0

We add all the numbers together, and all the variables

3x(2x+1)-(3(x+1)-3(-2x+4))=0

We multiply parentheses

6x^2+3x-(3(x+1)-3(-2x+4))=0


We calculate terms in parentheses: -(3(x+1)-3(-2x+4)), so:

3(x+1)-3(-2x+4)

We multiply parentheses

3x+6x+3-12

We add all the numbers together, and all the variables

9x-9

Back to the equation:

-(9x-9)


We get rid of parentheses

6x^2+3x-9x+9=0

We add all the numbers together, and all the variables

6x^2-6x+9=0

a = 6; b = -6; c = +9;
Δ = b2-4ac
Δ = -62-4·6·9
Δ = -180
Delta is less than zero, so there is no solution for the equation