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3x(2x+1)=3x-2
We move all terms to the left:
3x(2x+1)-(3x-2)=0
We multiply parentheses
6x^2+3x-(3x-2)=0
We get rid of parentheses
6x^2+3x-3x+2=0
We add all the numbers together, and all the variables
6x^2+2=0
a = 6; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·6·2
Δ = -48
Delta is less than zero, so there is no solution for the equation
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