3x(2x+3)+2(x-3)=x(6x+1)-7

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Solution for 3x(2x+3)+2(x-3)=x(6x+1)-7 equation: 



3x(2x+3)+2(x-3)=x(6x+1)-7

We move all terms to the left:

3x(2x+3)+2(x-3)-(x(6x+1)-7)=0

We multiply parentheses

6x^2+9x+2x-(x(6x+1)-7)-6=0



We calculate terms in parentheses: -(x(6x+1)-7), so:

x(6x+1)-7

We multiply parentheses

6x^2+x-7

Back to the equation:

-(6x^2+x-7)



We add all the numbers together, and all the variables

6x^2+11x-(6x^2+x-7)-6=0

We get rid of parentheses

6x^2-6x^2+11x-x+7-6=0

We add all the numbers together, and all the variables

10x+1=0

We move all terms containing x to the left, all other terms to the right

10x=-1

x=-1/10

x=-1/10

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