3x(2x+4)+1=2x(3x+8)

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Solution for 3x(2x+4)+1=2x(3x+8) equation: 



3x(2x+4)+1=2x(3x+8)

We move all terms to the left:

3x(2x+4)+1-(2x(3x+8))=0

We multiply parentheses

6x^2+12x-(2x(3x+8))+1=0



We calculate terms in parentheses: -(2x(3x+8)), so:

2x(3x+8)

We multiply parentheses

6x^2+16x

Back to the equation:

-(6x^2+16x)



We get rid of parentheses

6x^2-6x^2+12x-16x+1=0

We add all the numbers together, and all the variables

-4x+1=0

We move all terms containing x to the left, all other terms to the right

-4x=-1

x=-1/-4

x=1/4

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