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3x(2x+4)+1=2x(3x+8)
We move all terms to the left:
3x(2x+4)+1-(2x(3x+8))=0
We multiply parentheses
6x^2+12x-(2x(3x+8))+1=0
We calculate terms in parentheses: -(2x(3x+8)), so:We get rid of parentheses
2x(3x+8)
We multiply parentheses
6x^2+16x
Back to the equation:
-(6x^2+16x)
6x^2-6x^2+12x-16x+1=0
We add all the numbers together, and all the variables
-4x+1=0
We move all terms containing x to the left, all other terms to the right
-4x=-1
x=-1/-4
x=1/4
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