3x(2x+4)=6(x2+1)

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Solution for 3x(2x+4)=6(x2+1) equation: 



3x(2x+4)=6(x2+1)

We move all terms to the left:

3x(2x+4)-(6(x2+1))=0

We add all the numbers together, and all the variables

-(6(+x^2+1))+3x(2x+4)=0

We multiply parentheses

-(6(+x^2+1))+6x^2+12x=0



We calculate terms in parentheses: -(6(+x^2+1)), so:

6(+x^2+1)

We multiply parentheses

6x^2+6

Back to the equation:

-(6x^2+6)



We add all the numbers together, and all the variables

6x^2+12x-(6x^2+6)=0

We get rid of parentheses

6x^2-6x^2+12x-6=0

We add all the numbers together, and all the variables

12x-6=0

We move all terms containing x to the left, all other terms to the right

12x=6

x=6/12

x=1/2

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