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3x(2x+5)=-10x+6-5x^2
We move all terms to the left:
3x(2x+5)-(-10x+6-5x^2)=0
We multiply parentheses
-(-10x+6-5x^2)+6x^2+15x=0
We get rid of parentheses
5x^2+6x^2+10x+15x-6=0
We add all the numbers together, and all the variables
11x^2+25x-6=0
a = 11; b = 25; c = -6;
Δ = b2-4ac
Δ = 252-4·11·(-6)
Δ = 889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{889}}{2*11}=\frac{-25-\sqrt{889}}{22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{889}}{2*11}=\frac{-25+\sqrt{889}}{22} $
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