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3x(2x-1)=7
We move all terms to the left:
3x(2x-1)-(7)=0
We multiply parentheses
6x^2-3x-7=0
a = 6; b = -3; c = -7;
Δ = b2-4ac
Δ = -32-4·6·(-7)
Δ = 177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{177}}{2*6}=\frac{3-\sqrt{177}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{177}}{2*6}=\frac{3+\sqrt{177}}{12} $
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