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3x(2x-44)=56
We move all terms to the left:
3x(2x-44)-(56)=0
We multiply parentheses
6x^2-132x-56=0
a = 6; b = -132; c = -56;
Δ = b2-4ac
Δ = -1322-4·6·(-56)
Δ = 18768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{18768}=\sqrt{16*1173}=\sqrt{16}*\sqrt{1173}=4\sqrt{1173}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-132)-4\sqrt{1173}}{2*6}=\frac{132-4\sqrt{1173}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-132)+4\sqrt{1173}}{2*6}=\frac{132+4\sqrt{1173}}{12} $
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