3x(2x-5)4=0

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Solution for 3x(2x-5)4=0 equation:



3x(2x-5)4=0
We multiply parentheses
24x^2-60x=0
a = 24; b = -60; c = 0;
Δ = b2-4ac
Δ = -602-4·24·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-60}{2*24}=\frac{0}{48} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+60}{2*24}=\frac{120}{48} =2+1/2 $

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