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3x(2x-6)=44
We move all terms to the left:
3x(2x-6)-(44)=0
We multiply parentheses
6x^2-18x-44=0
a = 6; b = -18; c = -44;
Δ = b2-4ac
Δ = -182-4·6·(-44)
Δ = 1380
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1380}=\sqrt{4*345}=\sqrt{4}*\sqrt{345}=2\sqrt{345}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{345}}{2*6}=\frac{18-2\sqrt{345}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{345}}{2*6}=\frac{18+2\sqrt{345}}{12} $
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