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3x(2x-6)=5x
We move all terms to the left:
3x(2x-6)-(5x)=0
We add all the numbers together, and all the variables
-5x+3x(2x-6)=0
We multiply parentheses
6x^2-5x-18x=0
We add all the numbers together, and all the variables
6x^2-23x=0
a = 6; b = -23; c = 0;
Δ = b2-4ac
Δ = -232-4·6·0
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-23}{2*6}=\frac{0}{12} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+23}{2*6}=\frac{46}{12} =3+5/6 $
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