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3x(2x-7)=-5(2x-12)
We move all terms to the left:
3x(2x-7)-(-5(2x-12))=0
We multiply parentheses
6x^2-21x-(-5(2x-12))=0
We calculate terms in parentheses: -(-5(2x-12)), so:We get rid of parentheses
-5(2x-12)
We multiply parentheses
-10x+60
Back to the equation:
-(-10x+60)
6x^2-21x+10x-60=0
We add all the numbers together, and all the variables
6x^2-11x-60=0
a = 6; b = -11; c = -60;
Δ = b2-4ac
Δ = -112-4·6·(-60)
Δ = 1561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{1561}}{2*6}=\frac{11-\sqrt{1561}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{1561}}{2*6}=\frac{11+\sqrt{1561}}{12} $
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