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3x(2x-9)=2x-1
We move all terms to the left:
3x(2x-9)-(2x-1)=0
We multiply parentheses
6x^2-27x-(2x-1)=0
We get rid of parentheses
6x^2-27x-2x+1=0
We add all the numbers together, and all the variables
6x^2-29x+1=0
a = 6; b = -29; c = +1;
Δ = b2-4ac
Δ = -292-4·6·1
Δ = 817
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-\sqrt{817}}{2*6}=\frac{29-\sqrt{817}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+\sqrt{817}}{2*6}=\frac{29+\sqrt{817}}{12} $
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