3x(3x)+MB=4(x(x)+2)

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Solution for 3x(3x)+MB=4(x(x)+2) equation:


Simplifying
3x(3x) + MB = 4(x(x) + 2)

Remove parenthesis around (3x)
3x * 3x + MB = 4(x(x) + 2)

Reorder the terms for easier multiplication:
3 * 3x * x + MB = 4(x(x) + 2)

Multiply 3 * 3
9x * x + MB = 4(x(x) + 2)

Multiply x * x
9x2 + MB = 4(x(x) + 2)

Reorder the terms:
BM + 9x2 = 4(x(x) + 2)

Multiply x * x
BM + 9x2 = 4(x2 + 2)

Reorder the terms:
BM + 9x2 = 4(2 + x2)
BM + 9x2 = (2 * 4 + x2 * 4)
BM + 9x2 = (8 + 4x2)

Solving
BM + 9x2 = 8 + 4x2

Solving for variable 'B'.

Move all terms containing B to the left, all other terms to the right.

Add '-9x2' to each side of the equation.
BM + 9x2 + -9x2 = 8 + 4x2 + -9x2

Combine like terms: 9x2 + -9x2 = 0
BM + 0 = 8 + 4x2 + -9x2
BM = 8 + 4x2 + -9x2

Combine like terms: 4x2 + -9x2 = -5x2
BM = 8 + -5x2

Divide each side by 'M'.
B = 8M-1 + -5x2M-1

Simplifying
B = 8M-1 + -5x2M-1

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