3x(3x+16)=-64

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Solution for 3x(3x+16)=-64 equation: 



3x(3x+16)=-64

We move all terms to the left:

3x(3x+16)-(-64)=0

We add all the numbers together, and all the variables

3x(3x+16)+64=0

We multiply parentheses

9x^2+48x+64=0

a = 9; b = 48; c = +64;
Δ = b2-4ac
Δ = 482-4·9·64
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-48}{18}=-2+2/3$

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