3x(3x+2)+5=-1x(4+2x)

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Solution for 3x(3x+2)+5=-1x(4+2x) equation: 



3x(3x+2)+5=-1x(4+2x)

We move all terms to the left:

3x(3x+2)+5-(-1x(4+2x))=0

We add all the numbers together, and all the variables

3x(3x+2)-(-1x(2x+4))+5=0

We multiply parentheses

9x^2+6x-(-1x(2x+4))+5=0



We calculate terms in parentheses: -(-1x(2x+4)), so:

-1x(2x+4)

We multiply parentheses

-2x^2-4x

Back to the equation:

-(-2x^2-4x)



We get rid of parentheses

9x^2+2x^2+4x+6x+5=0

We add all the numbers together, and all the variables

11x^2+10x+5=0

a = 11; b = 10; c = +5;
Δ = b2-4ac
Δ = 102-4·11·5
Δ = -120
Delta is less than zero, so there is no solution for the equation

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