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3x(3x+20)=110
We move all terms to the left:
3x(3x+20)-(110)=0
We multiply parentheses
9x^2+60x-110=0
a = 9; b = 60; c = -110;
Δ = b2-4ac
Δ = 602-4·9·(-110)
Δ = 7560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7560}=\sqrt{36*210}=\sqrt{36}*\sqrt{210}=6\sqrt{210}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-6\sqrt{210}}{2*9}=\frac{-60-6\sqrt{210}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+6\sqrt{210}}{2*9}=\frac{-60+6\sqrt{210}}{18} $
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