3x(3x+3)=54

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Solution for 3x(3x+3)=54 equation:



3x(3x+3)=54
We move all terms to the left:
3x(3x+3)-(54)=0
We multiply parentheses
9x^2+9x-54=0
a = 9; b = 9; c = -54;
Δ = b2-4ac
Δ = 92-4·9·(-54)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-45}{2*9}=\frac{-54}{18} =-3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+45}{2*9}=\frac{36}{18} =2 $

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