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3x(3x+6)=135
We move all terms to the left:
3x(3x+6)-(135)=0
We multiply parentheses
9x^2+18x-135=0
a = 9; b = 18; c = -135;
Δ = b2-4ac
Δ = 182-4·9·(-135)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-72}{2*9}=\frac{-90}{18} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+72}{2*9}=\frac{54}{18} =3 $
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