3x(3x-10)+25=(3x-5)

Solution for 3x(3x-10)+25=(3x-5) equation:

3x(3x-10)+25=(3x-5)

We move all terms to the left:

3x(3x-10)+25-((3x-5))=0

We multiply parentheses

9x^2-30x-((3x-5))+25=0


We calculate terms in parentheses: -((3x-5)), so:

(3x-5)

We get rid of parentheses

3x-5

Back to the equation:

-(3x-5)


We get rid of parentheses

9x^2-30x-3x+5+25=0

We add all the numbers together, and all the variables

9x^2-33x+30=0

a = 9; b = -33; c = +30;
Δ = b2-4ac
Δ = -332-4·9·30
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-3}{2*9}=\frac{30}{18}
=1+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+3}{2*9}=\frac{36}{18}
=2
$