3x(3x-4)+4=0

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Solution for 3x(3x-4)+4=0 equation: 



3x(3x-4)+4=0

We multiply parentheses

9x^2-12x+4=0

a = 9; b = -12; c = +4;
Δ = b2-4ac
Δ = -122-4·9·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{12}{18}=2/3$

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