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3x(3x-4)=25-12x
We move all terms to the left:
3x(3x-4)-(25-12x)=0
We add all the numbers together, and all the variables
3x(3x-4)-(-12x+25)=0
We multiply parentheses
9x^2-12x-(-12x+25)=0
We get rid of parentheses
9x^2-12x+12x-25=0
We add all the numbers together, and all the variables
9x^2-25=0
a = 9; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·9·(-25)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-30}{2*9}=\frac{-30}{18} =-1+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+30}{2*9}=\frac{30}{18} =1+2/3 $
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