3x(3x-6)=0

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Solution for 3x(3x-6)=0 equation:



3x(3x-6)=0
We multiply parentheses
9x^2-18x=0
a = 9; b = -18; c = 0;
Δ = b2-4ac
Δ = -182-4·9·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-18}{2*9}=\frac{0}{18} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+18}{2*9}=\frac{36}{18} =2 $

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