3x(4-4x)=0

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Solution for 3x(4-4x)=0 equation:



3x(4-4x)=0
We add all the numbers together, and all the variables
3x(-4x+4)=0
We multiply parentheses
-12x^2+12x=0
a = -12; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-12)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-12}=\frac{-24}{-24} =1 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-12}=\frac{0}{-24} =0 $

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